Question

I’m writing a news script, and I’m having trouble making a way for the files to be deleted.

How can I change this script so that the <input type="checkbox" /> has a value of the file in the same row?

<?php
    // This function reads all available news
    function getNewsList(){

       $fileList = array();

        // Open the actual directory
        if ($handle = opendir("news")) {
            // Read all file from the actual directory
            while ($file = readdir($handle))  {
                if (!is_dir($file)) {
                    $fileList[] = $file;
            }
            }
        }   

        rsort($fileList);

        return $fileList;
    }

    // new

    $list = getNewsList();
    print("<table>\n");
    print("<tr><td>&nbsp;</td><td>Article Title:</td><td>Post Date:</td></tr>\n");
    foreach ($list as $value) {
        $newsData = file("news/".$value);
        $newsTitle  = $newsData[0];
        $submitDate = $newsData[1]; 
        unset ($newsData['0']);
        unset ($newsData['1']);

        $newsContent = "";
        foreach ($newsData as $value) {
            $newsContent .= $value;
        }

            print("<tr>");
            print("<td><input type=\"checkbox\" name=\"check_files[]\" value=\"$file\" /></td>");
            print("<td>$newsTitle</td>");
            print("<td>");
            print("$submitDate");
            print("</td>");
            print("</tr>\n");

    }  
    print("</table>\n");

I have a similar script for managing files, and it’s something like $dirArray[$index] for the file name, but I can’t figure out how to adapt this script to work the same way, because I’m too new to PHP.

Thanks for the help!

EDIT: This is the line where the file name needs to be: (instead of $file, which doesn’t work for some reason):

print("<td><input type=\"checkbox\" name=\"check_files[]\" value=\"$file\" /></td>");

Answer 1

The $file variable isn’t defined anywhere, you could try this:

replace

$newsData = file("news/".$value);

with

$file="news/".$value;
$newsData = file($file);