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Home/ Questions/Q 8720009
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Editorial Team
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Editorial Team
Asked: June 13, 20262026-06-13T06:56:03+00:00 2026-06-13T06:56:03+00:00

I’m writing a program that does many things, but one of them is converting

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I’m writing a program that does many things, but one of them is converting Celcius to Fahrenheit. After I did this, I decided to allow the reverse, so that’s what I’ve done. I get correct answers when I convert Celcius to Fahrenheit, but for some reason I’m getting slightly off answers when converting Fahrenheit to Celcius. Here’s my code:

String celcius = jTextArea3.getText();
String fahren = jTextArea7.getText();
if (fahren.equals("")) {
    double tempFahr;
    double Input = Double.parseDouble(jTextArea3.getText());

     tempFahr = Input * 9 / 5 + 32;
        jTextArea7.setText(tempFahr + "");
}
else
{
    double tempCelc;
    double Input = Double.parseDouble(jTextArea7.getText());

     tempCelc = (Input -32) * 5 / 9;
        jTextArea3.setText(tempCelc + "");
}

It’s simple code, but I’m wondering if it could be something very small that I’m not seeing. It could be my formula I suppose, but I’m pretty sure it’s not, I’ve looked into it. Can anyone help?

An example of the off answers I get is:
1 Celcius = 33.8 Fahrenheit
33.8 Fahrenheit = 0.9999999999999984 Celcius

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  1. Editorial Team
    Editorial Team
    2026-06-13T06:56:04+00:00Added an answer on June 13, 2026 at 6:56 am

    @Greg is right

    You just need to do some rounding:

    final int precision = 6 // try some different values here, from 2 to... 8?
    
    jTextArea3.setText(String.format("%." + precision + "f", tempCelc));
    

    Anyway – don’t worry your values are just fine, but to compare (or print, which is current use case) them
    you need some epsilon/precision, because – again: floating point calculations are almost never “exact”.

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