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Home/ Questions/Q 810147
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Editorial Team
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Editorial Team
Asked: May 15, 20262026-05-15T00:50:19+00:00 2026-05-15T00:50:19+00:00

I’m writing a program which listens to an incoming TcpClient and handles data when

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I’m writing a program which listens to an incoming TcpClient and handles data when it arrives. The Listen() method is run on a separate thread within the component, so it needs to be threadsafe. If I break out of a do while loop while I’m within a lock() statement, will the lock be released? If not, how do I accomplish this?

Thanks!

(Any other advice on the subject of Asynchronous TCP Sockets is welcome as well.)

private void Listen()
{
    do
    {
        lock (_clientLock)
        {
            if (!_client.Connected) break;
            lock (_stateLock)
            {
                if (!_listening) break;
                if (_client.GetStream().DataAvailable) HandleData();
            }
        }
        Thread.Sleep(0);
    } while (true);
}
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-15T00:50:20+00:00Added an answer on May 15, 2026 at 12:50 am

    Yes. The lock statement translates into a try/finally clause. In C# 4, for example, a lock statement like so:

    lock(obj)
    {
        // body
    }
    

    roughly translates (taken from Eric Lippert’s blog here) to:

    bool lockWasTaken = false;
    var temp = obj;
    try 
    { 
        Monitor.Enter(temp, ref lockWasTaken); 
        { 
           // body 
        }
    }
    finally 
    { 
        if (lockWasTaken) 
            Monitor.Exit(temp); 
    }
    

    When the execution leaves the scope of the lock {}, the underlying lock will be released automatically. This will happen no matter how you exit scope (break/return/etc), since the call to Monitor.Exit is wrapped, internally, inside of the finally block of a try/finally.

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