Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 6588217
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 25, 20262026-05-25T17:01:13+00:00 2026-05-25T17:01:13+00:00

I’m writing a regular expression that should do the following: == Text == Other

  • 0

I’m writing a regular expression that should do the following:

== Text ==
Other text
==     Text==

Becomes

<h2>Text</h2>
<p>Other text</p>
<h2>Text</h2>

I’m almost there, the problem is that this is what I currently get:

<h2>Text</h2>
<p>Other text</p>
<h2>Text</h2>
<p></p>

Even though it’s unlikely the heading will not be followed by text, I want to fix it at least for learning purposes.

Here is my function:

preg_replace('/== *(.*?) *==([^=]*)/m', 
             '<h2>$1</h2>
              <p>$2</p>
             ', '== Text ==
                 Other text
                 ==     Text==');

So basically, I want to ignore the <p></p> part if $2 is empty.

Any other tips / improvements are welcomed, I want to learn 🙂

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-25T17:01:14+00:00Added an answer on May 25, 2026 at 5:01 pm

    You need one simple conditional to prevent the empty <p> tag from appearing. While I would not recommend this usually, the easiest way to insert this simple if is by using the /e regex modifier to preg_replace:

    preg_replace('/== *(.*?) *==([^=]*)/me', 
                 '"<h2>$1</h2>".(trim("$2") == ""?"":"<p>$2</p>")',
                 '== Text ==
                     Other text
                  ==     Text==');
    

    This modifier makes the replacement string be evaluated as PHP code before making the replacement, so you can fit a small conditional in there easily.

    See it in action.

    Another option would be to use preg_replace_callback, which is effectively the same idea only that you now write the code as a separate function. This is better IMHO because it makes for clearer code.

    As a final note, if you intend to add more formatting options you might want to consider breaking your parsing down into multiple steps and possibly processing one line at a time because regular expressions are not designed to handle this kind of processing. You can force it up to a point, but then it starts to become very unmaintainable very quickly.

    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

I'm parsing an RSS feed that has an &#8217; in it. SimpleXML turns this
For some reason, after submitting a string like this Jack’s Spindle from a text
I am currently running into a problem where an element is coming back from
I ran into a problem. Wrote the following code snippet: teksti = teksti.Trim() teksti
I have a string like this: La Torre Eiffel paragonata all&#8217;Everest What PHP function
I'm working with an upstream system that sometimes sends me text destined for HTML/XML
link Im having trouble converting the html entites into html characters, (&# 8217;) i
That's pretty much it. I'm using Nokogiri to scrape a web page what has
this is what i have right now Drawing an RSS feed into the php,
I've got a string that has curly quotes in it. I'd like to replace

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.