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Editorial Team
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Editorial Team
Asked: May 11, 20262026-05-11T22:05:34+00:00 2026-05-11T22:05:34+00:00

I’m writing a script where icons rotate around a given pivot (or origin). I’ve

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I’m writing a script where icons rotate around a given pivot (or origin). I’ve been able to make this work for rotating the icons around an ellipse but I also want to have them move around the perimeter of a rectangle of a certain width, height and origin.

I’m doing it this way because my current code stores all the coords in an array with each angle integer as the key, and reusing this code would be much easier to work with.

If someone could give me an example of a 100×150 rectangle, that would be great.

EDIT: to clarify, by rotating around I mean moving around the perimeter (or orbiting) of a shape.

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  1. Editorial Team
    Editorial Team
    2026-05-11T22:05:34+00:00Added an answer on May 11, 2026 at 10:05 pm

    You know the size of the rectangle and you need to split up the whole angle interval into four different, so you know if a ray from the center of the rectangle intersects right, top, left or bottom of the rectangle.

    If the angle is: -atan(d/w) < alfa < atan(d/w) the ray intersects the right side of the rectangle. Then since you know that the x-displacement from the center of the rectangle to the right side is d/2, the displacement dy divided by d/2 is tan(alfa), so

    dy = d/2 * tan(alfa)

    You would handle this similarily with the other three angle intervals.

    Ok, here goes. You have a rect with width w and depth d. In the middle you have the center point, cp. I assume you want to calculate P, for different values of the angle alfa.

    alt text

    I divided the rectangle in four different areas, or angle intervals (1 to 4). The interval I mentioned above is the first one to the right. I hope this makes sense to you.

    First you need to calculate the angle intervals, these are determined completely by w and d. Depending on what value alfa has, calculate P accordingly, i.e. if the “ray” from CP to P intersects the upper, lower, right or left sides of the rectangle.

    Cheers

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