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Editorial Team
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Asked: 2026-05-13T23:05:06+00:00

I’m writing a shell script and I need to strip FIND ME out of

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I’m writing a shell script and I need to strip FIND ME out of something like this:

* *[**FIND ME**](find me)*

and assign it to an array. I had the code working flawlessly .. until I moved the script in Solaris to a non-global zone. Here is the code I used before:

objectArray[$i]=`echo $line | nawk -F '*[**|**]' '{print $2}'`

Now Prints:

awk: syntax error near line 1  
awk: bailing out near line 1

It was suggested that I try the same command with nawk, but I receive this error now instead:

nawk: illegal primary in regular expression `* *[**|**]` at  `*[**|**]`
 input record number 1
 source line number 1

Also, /usr/xpg4/bin/awk does not exist.

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1 Answer

  1. Editorial Team

    I think you need to be clearer on what you want to get. For me your awk line doesn’t ‘strip FIND ME out’

    echo "* *[**FIND ME**](find me)*" | nawk -F '* *[**|**]' '{print $2}'
[

    So it would help if you gave some examples of the input/output you are expecting. Maybe there’s a way to do what you want with sed?

    EDIT:

    From comments you actually want to select “FIND ME” from line, not strip it out.

    I guess the dialect of regular expressions accepted by this nawk is different than gawk. So maybe a tool that’s better suited to the job is in order.

    echo "* *[**FIND ME**](find me)*" | sed -e"s/.*\* \*\[\*\*\(.[^*]*\)\*\*\].*/\1/"
FIND ME
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