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Home/ Questions/Q 7715705
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Editorial Team
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Editorial Team
Asked: June 1, 20262026-06-01T02:27:15+00:00 2026-06-01T02:27:15+00:00

I’m writing a small function to generate values from the Normal distribution using Box-Muller

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I’m writing a small function to generate values from the Normal distribution using Box-Muller method, but I’m getting negative values.

Here is my source code

import random

def generate_normal(mu, sigma):
    u = random.random()
    v = random.random()

    z1 = sqrt(-2 * log(u)) * sin(2 * pi * v)
    z2 = sqrt(-2 * log(u)) * cos(2 * pi * v)

    x1 = mu + z1 * sigma
    x2 = mu + z2 * sigma

    return x2

Waht am I missing? I’m getting negative values in both x1 and x2. For example:

mu: 400
sigma: 150
u: 7.27333176449e-05
v: 0.642384573173
z1: -3.40497345242
x1: -110.746017863

and:

x2: -9.79324023117
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-01T02:27:17+00:00Added an answer on June 1, 2026 at 2:27 am

    The unit normal distribution is centred on zero, and two-sided with small tails out to plus and minus infinity. 99.7% of your values will lie within three standard deviations, the other 0.3% won’t.

    enter image description here

    In this example, with a mean of 400 and a standard deviation of 150, 99.7% of your values will fall within three standard deviations of the mean – the interval [-50,850], which includes negative numbers. So expect negative numbers right off the bat.

    As for the other 0.3% of values, remember that’s 3/1000 of your numbers – not uncommon at all.

    If you want a “bell-curvey” distribution with finite support, try the beta distribution.

    Finally, unless this is an academic exercise, there’s no need to roll your own equivalent to numpy.random.normal().

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