Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • Home
  • SEARCH
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 7028973
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 28, 20262026-05-28T00:28:37+00:00 2026-05-28T00:28:37+00:00

I’m writing a small web server, and having a problem with parsing a request.

  • 0

I’m writing a small web server, and having a problem with parsing a request. I parse a BufferedReader into a LinkedList (so that I can perform operation based on POST data sent.) I found this answer explaining that the buffer isn’t terminated due to the connection hanging open. I’m not sure how to close it.

How I open the socket (and how I thought to close it):

            Socket connectionSocket = serverSocket.accept();
            InetAddress client = connectionSocket.getInetAddress();

            System.out.println(client.getHostName() + " connected to server.");

            BufferedReader input = new BufferedReader(new InputStreamReader(connectionSocket.getInputStream(), "UTF-8"));

            DataOutputStream output = new DataOutputStream(connectionSocket.getOutputStream());

            output.writeUTF(httpHeader(200));

            httpHandler(input, output);

            connectionSocket.close();

The httpHeader method forms a simple string with “HTTP/1.0” on the first line, and in this case, “200 OK” on the next line and a new line at the end. The POST request that is sent is HTTP 1.0.

Being as concise as I could manage, my question is two-fold: How do I properly respond to and close a HTTP 1.0 POST request/socket?

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-28T00:28:38+00:00Added an answer on May 28, 2026 at 12:28 am

    A POST request has associated data, and MUST be accompanied by a Content-Length header specifying the exact length of that POST data.

    So, you must first real all HTTP headers, decode the Content-Length, and then read the POST data (which is, as is classical with HTTP, separated from the headers by an empty line).

    If the amount of data is not sufficient, or there is too much of it, or you don’t even receive a Content-Length header, then you should return 400.

    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

link Im having trouble converting the html entites into html characters, (&# 8217;) i
I have a French site that I want to parse, but am running into
I'm parsing an RSS feed that has an ’ in it. SimpleXML turns this
That's pretty much it. I'm using Nokogiri to scrape a web page what has
I am currently running into a problem where an element is coming back from
I ran into a problem. Wrote the following code snippet: teksti = teksti.Trim() teksti
I used javascript for loading a picture on my website depending on which small
I have a jquery bug and I've been looking for hours now, I can't
this is what i have right now Drawing an RSS feed into the php,
I've got a string that has curly quotes in it. I'd like to replace

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.