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Home/ Questions/Q 976935
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Editorial Team
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Editorial Team
Asked: May 16, 20262026-05-16T03:49:30+00:00 2026-05-16T03:49:30+00:00

I’m writing a template class which should take an array as its type. public

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I’m writing a template class which should take an array as its type.

public class Foo<T> {...}

How best can I enforce that “T” is an array type? (int[], Bar[], …) Preferably compile time if possible, obviously, but otherwise what is the best way at debug run time to throw an exception or something if T is not an array?

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  1. Editorial Team
    Editorial Team
    2026-05-16T03:49:30+00:00Added an answer on May 16, 2026 at 3:49 am

    It is not possible to do it exactly how you have asked and have the generic type specify an array or primitive.

    The syntax allows for things like:

    public class Foo <az09$_ extends MyClassOrInterface & Serializable & Closeable> {...}
    

    Where az09$_ is any valid identifier that may also be parameterized with an identically formatted generic type.

    But az09$_ is restricted to being a java identifier, so you cannot do public class Foo<T[]> {...} any more than you can do public class Foo[] {...}.

    Typically you would do what you are after in your usage of T, i.e:

    public class Foo<T> {
    
        public T[] processIt(T... ts) {
            // do something
            return ts;
        } 
    
    }
    
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