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Home/ Questions/Q 5935087
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Editorial Team
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Editorial Team
Asked: May 22, 20262026-05-22T15:12:15+00:00 2026-05-22T15:12:15+00:00

I’m writing a utility module for easy handling of data text files. I have

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I’m writing a utility module for easy handling of data text files. I have declared some module-level constants to provide default values to my methods arguments since for now I only use these values but I want my code to be easily adaptable.

But some constants aren’t easily hard-coded. For example re‘s pattern objects I can only get with re.compile. So I’ve written

import re

_my_fine_pattern_string = r"some obnoxious regex"
MY_FINE_PATTERN         = re.compile(_my_fine_pattern_string)

def spam(eggs):
...

It worked yesterday within a script I directly execute. But now I wonder. Will this code be executed on import? Will it slow the execution? Will I be burned for doing this? Is there a better/faster way to do it?

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  1. Editorial Team
    Editorial Team
    2026-05-22T15:12:16+00:00Added an answer on May 22, 2026 at 3:12 pm

    Yes, this is fine. It will be executed on import. If you have a significant amount of computation to do (which re.compile isn’t), it will slow down the import — but this is as it should be, since you need the constants to do your work anyway.

    Why are you using double-underscore names? If the constants are meant to be exported they should not be prefixed with underscores, and if not then they should have a single underscore. (Double has a specific meaning in the context of class inheritance but shouldn’t generally be used anywhere else.)

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