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Home/ Questions/Q 6753625
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T13:11:02+00:00 2026-05-26T13:11:02+00:00

I’m writing a wrapper for a braindead enterprise XML API. I have an XDocument

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I’m writing a wrapper for a braindead enterprise XML API. I have an XDocument that I need to turn into a string. Due to the fact that their XML parser is so finicky that it cannot even handle whitespace between XML nodes, the document declaration MUST be EXACTLY:

<?xml version="1.0"?>

However, the XDocument.Save() method always adds an encoding attribute in that declaration:

<?xml version="1.0" encoding="utf-16"?>

With the past hour spent on Google and Stack looking for the best way to generate the XML string, the best I can do is:

string result = xmlStringBuilder.ToString().Replace(@"encoding=""utf-16"", string.Empty));

I’ve tried

xdoc.Declaration = new XDeclaration("1.0", null, null);

and that does succeed at setting the declaration in the XDocument the way I want it; however, when I call the Save() method, the encoding attribute gets magically thrown back in there, no matter what route I go (using TextWriter, adding XmlWriterSettings, etc.).

Does anyone have a better way to do this, or is my code forever doomed to have a paragraph of ranting in comments above the hideous string replace?

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  1. Editorial Team
    Editorial Team
    2026-05-26T13:11:03+00:00Added an answer on May 26, 2026 at 1:11 pm

    Well the receiving end should be fixed to use an XML parser and not something that breaks with XML syntax but with .NET if you want to create a string with the XML declaration as you posted it the following approach works for me:

    public class MyStringWriter : StringWriter
    {
        public override Encoding Encoding
        {
            get
            {
                return null;
            }
        }
    }
    

    and then

        XDocument doc = new XDocument(
            new XDeclaration("1.0", null, null),
            new XElement("root", "test")
            );
    
        string xml;
    
        using (StringWriter msw = new MyStringWriter())
        {
            doc.Save(msw);
            xml = msw.ToString();
        }
    
        Console.WriteLine(xml);
    

    outputs

    <?xml version="1.0"?>
    <root>test</root>
    
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