Question

I’m writing an accounting system with PHP and MySQL and using PDO for working with database. In the payment page, I must have 2 drop down lists from defined accounts.
At the first, I’ve used a simple query to fetch all records for accounts.

$sql = "SELECT id,title FROM tbl_accounts WHERE uid = ? ORDER BY title";
$q = $db->prepare($sql);
$q->execute(array($uid));

I have put fetched rows in a drop down list and everything was ok.

<select name="account_id2" class="medium" id="account_id2">
    <option value="null">---</option>
    <?php
    while ($r = $q->fetch()) {
        echo '<option value="'.$r['id'].'">'.$r['title'].'</option>';
    }
    ?>
</select>

But when I wanted to make second drop down list using fetched records, nothing have been shown. So I thought I had to create another query for it. I did it and second one made correctly.
But my question is: Can not we use fetched data more than 1 time ? If I needed 3rd drop down, I had to write another query?

Answer 1

Depending on your conditional loop, you may need to reset the array pointer using reset().

Update:

To reset a result set you can use data_seek() or built a separate array as noted in the other answers.