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Home/ Questions/Q 7571791
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Editorial Team
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Editorial Team
Asked: May 30, 20262026-05-30T15:45:26+00:00 2026-05-30T15:45:26+00:00

I’m writing an algorithm in OpenCL in which I’d need every work unit to

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I’m writing an algorithm in OpenCL in which I’d need every work unit to remember a fair portion of data, say something between a long[70] and a long[200] or so per kernel.

Recent AMD devices have 32 KiB __local memory, which is (for the given amount of data per kernel) enough to store the info for 20-58 work units. However, from what I understand from the architecture (and especially from this drawing), each shader core also has a dedicated amount of private memory. I however fail to find its size.

Can anyone tell me how to find out how much private memory each kernel has?

I’m particularly curious about the HD7970, since I plan to buy some of these soon.

Edit: Problem solved, the answer is here in appendix D.

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  1. Editorial Team
    Editorial Team
    2026-05-30T15:45:27+00:00Added an answer on May 30, 2026 at 3:45 pm

    The answer was given by user talonmies in the comments, so I’ll write it in a new answer here to close the question.

    These values can be found in Appendix D of the AMD APP OpenCL Programming Guide http://developer.amd.com/sdks/amdappsdk/assets/amd_accelerated_parallel_processing_opencl_programming_guide.pdf (a similar document exists for nVidia). Apparently a register is 128 bits (4×32) for AMD devices and there are 16384 registers for all modern high-end devices, so that’s a remarkable 256KB per compute unit.

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