Question

I’m writing an app which should send a file to PHP server. Here is my code:

    InputStream is = new FileInputStream(file);
    HttpClient httpClient = new DefaultHttpClient();
    HttpPost postRequest = new HttpPost("http://majkelsoftgames.cba.pl/ser/server.php");

    byte[] data = IOUtils.toByteArray(is);
    InputStreamBody isb= new InputStreamBody(new ByteArrayInputStream(data), "file");

    MultipartEntity multipartContent = new MultipartEntity();
    multipartContent.addPart("file", isb);

    postRequest.setEntity(multipartContent);
    HttpResponse response = httpClient.execute(postRequest);

My problem is that I really dont have experience in PHP and I dont know how to
pick up this file on PHP side. I found some code:

<?php
    $target_path  = "./";
    $target_path = $target_path . basename( $_FILES['uploadedfile']['name']);

    if(move_uploaded_file($_FILES['uploadedfile']['tmp_name'], $target_path)) {
        echo "The file ".  basename( $_FILES['uploadedfile']['name'])." has been uploaded";
    } 
    else {
        echo "There was an error uploading the file, please try again!";
    }
?>

But it does not work. Can someone explain me how can I simply pick up fine on PHP side?

Answer 1

I think the issue is here:

InputStreamBody isb= new InputStreamBody(new ByteArrayInputStream(data), "file");

This is sending the data with the name “file”, but then

$_FILES['uploadedfile']['name']

is trying to find a file named “uploadedfile”. Make sure they match.