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Home/ Questions/Q 335021
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Editorial Team
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Editorial Team
Asked: May 12, 20262026-05-12T10:06:36+00:00 2026-05-12T10:06:36+00:00

I’m writing an implementation of std::codecvt facet that uses iconv. This implementation stores a

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I’m writing an implementation of std::codecvt facet that uses iconv. This implementation stores a pointer to heap-allocated data in std::mbstate_t state argument.

Everything works fine, but is this code 64-bit compatible?
Is there a platform where a pointer size exceeds the size of std::mbstate_t?

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  1. Editorial Team
    Editorial Team
    2026-05-12T10:06:36+00:00Added an answer on May 12, 2026 at 10:06 am

    Doesn’t the codecvt template take the state type as a parameter? Can you just use a pointer type there instead? I can’t remember whether the various classes that use a codecvt place requirements on the state type.

    Assuming that you can’t just change the state type… on MSVC 2008, mbstate_t is typedefd as an int. The standard only requires that int be larger than 16 bits and no larger than a long, so it’s not 64-bit safe. I guess you would need to store an index or key into some data structure instead of a pointer.

    update:

    The following compiles under VS2008, at least:

    std::wstring const in = L"input";
    size_t const buf_size = 256;
    char* buf = new char[buf_size];
    wchar_t const* char_next;
    char * byte_next;
    void* state = NULL;
    
    typedef std::codecvt<wchar_t, char, void*> codecvt_t;
    codecvt_t::result res =
        std::use_facet<codecvt_t>(std::locale()).out(
            state, in.c_str(), in.c_str() + in.length(),
            char_next, &buf[0], &buf[buf_size], byte_next);
    
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