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Home/ Questions/Q 5963883
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Editorial Team
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Editorial Team
Asked: May 22, 20262026-05-22T19:19:58+00:00 2026-05-22T19:19:58+00:00

I’m writing shadow removal for my pony detector . After I’ve converted a PNG

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I’m writing shadow removal for my pony detector. After I’ve converted a PNG image from sRGB to CIE XYZ I remove the luminance as per instructions:


When I try to convert the image back to sRGB for display, I get RGB values that fall outside the sRGB gamut (I get values greater than 255). Is this normal, or should I keep looking for bugs? Note: conversion to XYZ and back without modification produces no glitches.

Illustration (top left: original, bottom left: byte value wraparaund for red and blue hues):

For completeness: top right: color ratios, bottom right: convert to HSV and equalize value.

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  1. Editorial Team
    Editorial Team
    2026-05-22T19:19:59+00:00Added an answer on May 22, 2026 at 7:19 pm

    The final transformation does not remove the luminance, it creates two new values, x, y that together define the chromacity while Y contains the luminance. This is the key paragraph in your instructions link (just before the formulas you link):

    The CIE XYZ color space was
    deliberately designed so that the Y
    parameter was a measure of the
    brightness or luminance of a color.
    The chromaticity of a color was then
    specified by the two derived
    parameters x and y, two of the three
    normalized values which are functions
    of all three tristimulus values X, Y,
    and Z:

    What this means is that if you have an image of a surface that has a single colour, but a part of the surface is in the shadow, then in the xyY space the x and y values should be the same (or very similar) for all pixels on the surface whether they are in the shadow or not.

    The xyz values you get from the final transformation cannot be translated directly back to RGB as if they were XYZ values (note capitalization). So to answer your actual question: If you are using the xyz values as if they are XYZ values then there are no bugs in your code. Translation to RGB from that should not work using the formulas you linked.

    Now if you want to actually remove the shadows from the entire image what you do is:

    • scale your RGB values to be floating point valies in the [0-1] range by dividing each value by 255 (assuming 24-bit RGB). The conversion to floating point helps accuracy a lot!
    • Convert the image to xyY
    • Replace all Y values with one value, say 0.5, but experiment.
    • Reverse the transformation, from xyY to XYZ:

    X from xyY

    Z from xyY

    • then to RGB:

    XYZ to RGB

    • Then rescale your RGB values on the [0..255] interval.

    This should give you a very boring but shadowless version of your original image. Of course if your goal is detecting single colour regions you could also just do this on the xy values in the xyY image and use the regions you detect there on the original.

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