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Home/ Questions/Q 762393
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Editorial Team
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Editorial Team
Asked: May 14, 20262026-05-14T15:57:11+00:00 2026-05-14T15:57:11+00:00

I’m writing some functions in php using exec() to interrogate a svn. The commands

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I’m writing some functions in php using exec() to interrogate a svn.

The commands exec("svn list ".$myurl) works.

Now, I try to get a path on a svn repository with the checkout command.
When I put the command “svn checkout http://core.wordress.org/tags/2.9.2/ last-version” directly in the console, it works.

But when I do this from a php script using exec(), like this :

exec("svn checkout ".$myurl, $dir)

it doesn’t work.

Have you an idea ??

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  1. Editorial Team
    Editorial Team
    2026-05-14T15:57:12+00:00Added an answer on May 14, 2026 at 3:57 pm

    This can have a variety of reasons.

    • The user PHP runs under is not allowed to write into the directory you want to check out into

    • The SVN repository requires login credentials that are not cached for the user PHP runs under

    • The SVN checkout process starts, but requires some additional input like the dreaded “Do you want to accept this certificate” with unsigned certificates.

    Try adding 2>&1 to the command to redirect stderr to stdout, and take a look at $dir. Also make use of the $return_var parameter to exec().

    And as Jacob pointed out, always use escapeshellargs() for your command arguments.

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