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Home/ Questions/Q 6643863
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Editorial Team
  • 0
Editorial Team
Asked: May 26, 20262026-05-26T00:05:59+00:00 2026-05-26T00:05:59+00:00

Imagine I have a String array like this: String[][] fruits = {{Orange,1}, {Apple,2}, {Arancia,3};

  • 0

Imagine I have a String array like this:

String[][] fruits = {{"Orange","1"}, {"Apple","2"}, {"Arancia","3"};

If I do this:

     for (int i = 0; i < fruits.length;i++){
         System.out.println(fruits[i][0].charAt(1));
            }

it will print:

r
p
r

And if I do this:

     for (int i = 0; i < fruits.length;i++){
         Character compare = fruits[i][0].charAt(1);
         System.out.println(compare.equals('r'));
            }

it will print:

true
false
true

So here is my question. Is it possible to use charAt and equals on the same line, I mean, something like this:

System.out.println((fruits[i][0].charAt(1)).equals("r"));

Regards,

favolas

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  1. Editorial Team
    Editorial Team
    2026-05-26T00:05:59+00:00Added an answer on May 26, 2026 at 12:05 am

    Yes, provided you convert the result of charAt() to Character first:

    System.out.println(Character.valueOf(fruits[i][0].charAt(1)).equals('r'));
    

    A simpler version is to write

    System.out.println(fruits[i][0].charAt(1) == 'r');
    

    I personally would always prefer the latter to the former.

    The reason your version doesn’t work is that charAt() returns char (as opposed to Character), and char, being a primitive type, has no equals() method.

    Another error in your code is the use of double quotes in equals("r"). Sadly, this one would compile and could lead to a painful debugging session. With the char-based version above this would be caught at compile time.

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