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Home/ Questions/Q 6241153
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Editorial Team
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Editorial Team
Asked: May 24, 20262026-05-24T11:42:32+00:00 2026-05-24T11:42:32+00:00

Imagine that we have the following methods (pseudo C#): static IEnumerable<T> Iterator<T>() { switch

  • 0

Imagine that we have the following methods (pseudo C#):

static IEnumerable<T> Iterator<T>()
{
    switch (SomeCondition)
    {
        case CaseA:
            yield return default(T);
        case CaseB:
            yield return default(T);
            yield return default(T);
        case CaseC:
            yield return default(T);
        default:
            break;
    }
}

static IEnumerable<T> Array<T>()
{
    switch (SomeCondition)
    {
        case CaseA:
            return new[] { default(T) };
        case CaseB:
            return new[] { default(T), default(T) };
        case CaseC:
            return new[] { default(T) };
        default:
            break;
    }
}

Which one will consume less memory (and less GC cycles) if we have many calls to similar like this methods? Does it make sense to write your own Enumerable/Enumerator in order to implement this kind of Enumerable.Once() scenario?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-24T11:42:33+00:00Added an answer on May 24, 2026 at 11:42 am

    This one is faster than both the others:

    static T[] Array<T>()
    {
        switch (SomeCondition)
        {
            case CaseA:
                return new[1];
            case CaseB:
                return new[2];
            case CaseC:
                return new[1];
            default:
                break;
        }
    }
    

    But it really isn’t going to matter much.

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