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Home/ Questions/Q 1043761
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Editorial Team
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Editorial Team
Asked: May 16, 20262026-05-16T15:43:13+00:00 2026-05-16T15:43:13+00:00

Imagine the following two ejb3.0 stateless session beans, each implements a local interface and

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Imagine the following two ejb3.0 stateless session beans, each implements a local interface and they are deployed to the same container:

public class EjbA {
    @EJB 
    private ejbB;

    public void methodA() {
        for (int i=0; i<100; i++) {
            ejbB.methodB();
        }
    }    
}

public class EjbB {
    public void methodB() {
        ...
    }
}

When methodA is invoked, does each call to methodB cause a new transaction to begin and commit? Or, since these a both local beans, is there one transaction that begins when methodA is called and is re-used by methodB?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-16T15:43:14+00:00Added an answer on May 16, 2026 at 3:43 pm

    It depends on your transaction attribute – which you can set with the @TransactionAttribute annotation to one of:

    • REQUIRED
    • REQUIRES_NEW
    • SUPPORTS
    • MANDATORY
    • NOT_SUPPORTED
    • NEVER

    REQUIRED is the default, and will start a new transaction if there is no transaction in place, otherwise the container uses the existing transaction.

    REQUIRES_NEW tells the container to always start a new transaction.

    The other options are less commonly used in my experience – but they are all defined in the EJB specification.

    For example:

    @Stateless
    public class EjbA {
        @EJB 
        private ejbB;
    
        @TransactionAttribute(TransactionAttributeType.REQUIRES_NEW)
        public void methodA() {
            for (int i=0; i<100; i++) {
                ejbB.methodB();
            }
        }    
    }
    

    … would make methodA() always run in a new transaction.

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