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Home/ Questions/Q 7857173
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Editorial Team
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Editorial Team
Asked: June 2, 20262026-06-02T20:57:23+00:00 2026-06-02T20:57:23+00:00

Imagine these models: class User belongs_to :profile # has email here end class Profile

  • 0

Imagine these models:

class User
  belongs_to :profile
  # has email here
end

class Profile
  has_one :user
  # has first_name,last_name
end

and

class Post
  belongs_to :profile
  # has title,content
end

Now, I would like to query all posts ( do a LIKE “%substring%” ) on the user’s email. I would prefer to not have to write it with map/selects as I think it would generate pretty inefficient code. I tried something like that:

class Post
  def self.with_user_email_like(email)
    self.joins(:profile).where("profile.email LIKE ?","%#{email}%")
  end
end

The thing is, I know somehow I should have a profile.user.email in the condition above, but I just can’t get it to work. Any suggestions?

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  1. Editorial Team
    Editorial Team
    2026-06-02T20:57:24+00:00Added an answer on June 2, 2026 at 8:57 pm

    Try this

    class Post
      belongs_to :profile
      scope :with_user_email_like, lambda{|email| joins(:profile => :user).where("users.email LIKE %?%", email)} 
    end
    
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