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Home/ Questions/Q 670473
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Editorial Team
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Editorial Team
Asked: May 14, 20262026-05-14T00:16:00+00:00 2026-05-14T00:16:00+00:00

implicit val odkaz = head; def vypis(implicit odkaz:Prvek):String = { odkaz match{ case null

  • 0
implicit val odkaz = head;
def vypis(implicit odkaz:Prvek):String = {
    odkaz match{
        case null => ""
        case e => e.cislo + " " + e.pocet + "\n" + vypis(e.dalsi)
    }
}

…

def main(args:Array[String]){
    val q = new MyQueue() // insert some values
    println(q.vypis)
}

This method(vypis) is a member of an queue-class so I’ll always want to implicity start the recursion from the start of the queue, when calling the method from outside. Is there a way how to write it, that the method from outside calling, there’s no paramter, but in inside, there’s a parameter – for recursion…?
The compiler complains that the parameter is not defined when called from outside


Or is there are way how can specify the default value for a method’s parameter?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-14T00:16:01+00:00Added an answer on May 14, 2026 at 12:16 am

    Using a nested method

    def sum(list: List[Int]) = {
      @annotation.tailrec
      def sum(ls: List[Int], s: Int): Int = ls match { 
         case x :: xs => sum(xs, x + s)
         case _ => s
      }
      sum(list, 0)
    }
    

    Using a default parameter for the accumulator

    @annotation.tailrec
    def sum(list: List[Int], s: Int = 0): Int = list match { 
       case x :: xs => sum(xs, x + s)
       case _ => s
    }
    

    The second approach (only possible with Scala 2.8) unneccesarily broadens the public API, so I would recommend the first.

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