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Home/ Questions/Q 8457287
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Editorial Team
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Editorial Team
Asked: June 10, 20262026-06-10T12:46:23+00:00 2026-06-10T12:46:23+00:00

import Data.Dynamic default(Integer,Double) a :: Num a => a a = 5 — show

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import Data.Dynamic

default(Integer,Double)

a :: Num a => a
a = 5

-- show :: Show a => a -> String
-- toDyn :: Typeable a => a -> Dynamic

main :: IO ()
-- main = print $ show a -- *** THIS LINE WORKS WELL
main = print $ toDyn a   -- *** THIS LINE LEADS TO AN AMBIGUOUS TYPE ERROR

I don’t understand why the first “main” version works, and not the second.
Is there someone who can help me ?
Thanks in advance for your reply.

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  1. Editorial Team
    Editorial Team
    2026-06-10T12:46:25+00:00Added an answer on June 10, 2026 at 12:46 pm

    From the Haskell report:

    In situations where an ambiguous type is discovered, an ambiguous type variable, v, is defaultable if:

    • v appears only in constraints of the form C v, where C is a class, and
    • at least one of these classes is a numeric class, (that is, Num or a subclass of Num), and
    • all of these classes are defined in the Prelude or a standard library

    Your example fails because unlike Show, Typeable is not one of the classes specified in the third point, so no defaulting is performed.

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