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Home/ Questions/Q 6740237
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Editorial Team
  • 0
Editorial Team
Asked: May 26, 20262026-05-26T11:34:56+00:00 2026-05-26T11:34:56+00:00

import java.io.IOException; import java.util.*; public class task2 { public static void main (String []

  • 0
import java.io.IOException;
import java.util.*;

 public class task2 {
public static void main (String [] args) throws IOException {
    int a;
    int b;
    String y;
    String x;
    Scanner input = new Scanner(System.in);

    System.out.println("Please enter number A:");
    a = input.nextInt();

    System.out.println("\nPlease enter number B:");
    b = input.nextInt();

    System.out.println("\nLastly, enter A if you wish it to be the dividor and/or subtractor, or if you wish it to be B, please enter B :");             //stops running properly here...
    y=input.nextLine();

    System.out.println("\nWhat would you like to do? Multiply (*), Divide (/), Subtract (-) or  Add   (+)? Please enter the symbol of which process you would like to have completed:");
    x=input.nextLine();


    if (y=="b"+"B") {

    if (x=="*") {
    System.out.println("\nThe product of these numbers is:" + a*b);}
    else 
    if (x=="/") {
    System.out.println("\nThe quotient of these numbers is:" + a/b);}
    else 
    if (x=="+") {
    System.out.println("\nThe sum of these numbers is:" + a+b);}
    else 
    if (x=="-") {
    System.out.println("\nThe difference of these numbers is:" + (a-b));}}

    else 
    if (y=="a"+"A"){

    if (x=="*") {
    System.out.println("\nThe product of these numbers is:" + b*a);}
    else 
    if (x=="/") {
    System.out.println("\nThe quotient of these numbers is:" + b/a);}
    else 
    if (x=="+") {
    System.out.println("\nThe sum of these numbers is:" + b+a);}
    else 
    if (x=="-") {
    System.out.println("\nThe difference of these numbers is:" + (b-a));}}
}
}

I dont know why it stops but where indicated by “//” the program suddenly stops letting me input information and does not continue the processes i want it to do. I wont bother explaining the program in detial because i believe it is fairly obvious from the code itself what i want to do.
Thanks in adavance for all the help!

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-26T11:34:56+00:00Added an answer on May 26, 2026 at 11:34 am

    Use

    input.next();
    

    not

    input.nextLine();
    

    Since nextLine() skips over the input and sets the scanner to the NEXT line and returns a string representation of what was skipped. Your program throws the errow because the NEXT line does not exist

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