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Home/ Questions/Q 6762875
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T14:24:38+00:00 2026-05-26T14:24:38+00:00

import java.util.Scanner; public class EP55Out { public static void main(String[] args) { Scanner in

  • 0
import java.util.Scanner;

public class EP55Out
{

    public static void main(String[] args)
    {
        Scanner in = new Scanner(System.in);    
        System.out.print("Please enter a grade: ");
        String letter = in.next();
//         getNumericGrade(grade);
    }
    public static void getNumericGrade(double grade)
    {
        int spacer = 0;
        String first = letter.substring(0,1);
        String second = letter.substring(1,2);

        if (first.equalsIgnoreCase("a"))
        grade = 4.0;
        else if (first.equalsIgnoreCase("b"))
        grade = 3.0;
        else if (first.equalsIgnoreCase("c"))
        grade = 2.0;
        else if (first.equalsIgnoreCase("d"))
        grade = 1.0;
        else if (first.equalsIgnoreCase("f"))
        grade = 0;
        else grade = 9;

        if (second.equalsIgnoreCase("+"))
        grade += 0.3;
        else if (second.equalsIgnoreCase("-"))
        grade -= 0.3;
        else
        grade += 9;
        System.out.println(grade);
    }
}

I don’t know if you guys understand what I mean, but I keep getting the error that “grade” does not exist even though it is defined in the main. I know it has something to do with “void” but I have no clue what. Can anybody help?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-26T14:24:39+00:00Added an answer on May 26, 2026 at 2:24 pm

    So you are learning Java don’t you?

    I’ll try to explain what you are doing wrong.

    import java.util.Scanner;
    
    public class EP55Out {
    
        public static void main(String[] args){
            Scanner in = new Scanner(System.in);    
            System.out.print("Please enter a grade: ");
            String letter = in.next();
            //You need to give letter to the method
            getNumericGrade(letter);
        }
    
        //AND the method should need String and not double 
        public static void getNumericGrade(String letter){      
        //After this you need a real double value - lets call is grade;
            double grade = 0;
            int spacer = 0;
            String first = letter.substring(0,1);
            String second = letter.substring(1,2);
    
            //You cant to numeric stuff with a String- thats why we use our double here
            if (first.equalsIgnoreCase("a"))
            grade = 4.0;
            else if (first.equalsIgnoreCase("b"))
            grade = 3.0;
            else if (first.equalsIgnoreCase("c"))
            grade = 2.0;
            else if (first.equalsIgnoreCase("d"))
            grade = 1.0;
            else if (first.equalsIgnoreCase("f"))
            grade = 0;
            else grade = 9;
    
            if (second.equalsIgnoreCase("+"))
            grade += 0.3;
            else if (second.equalsIgnoreCase("-"))
            grade -= 0.3;
            else
            grade += 9;
            System.out.println(grade+"");
        }
    }
    

    You missed an important point with variables…
    If you define a variable in a method – it is only visible in THE DEFINING METHOD!

    So
    public static void getNumericGrade(String letter)
    cannot know that there is a letter variable in
    public static void main(String[] args)

    Hope I could help you 😉

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