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Home/ Questions/Q 6144193
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Editorial Team
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Editorial Team
Asked: May 23, 20262026-05-23T18:36:58+00:00 2026-05-23T18:36:58+00:00

import java.util.Scanner; public class Main { /** * @param args */ public static void

  • 0
import java.util.Scanner;


public class Main {

    /**
     * @param args
     */
    public static void main(String[] args) {
        // TODO Auto-generated method stub
        Scanner scan=new Scanner(System.in);
        int i,j;
        int count = 0;
        int test=scan.nextInt();
        String[] con=new String[test];
        while(test>0)
         {i=scan.nextInt();
         j=scan.nextInt();

             for(int k=i;k<=j;k++)
             if(prime(k))
//***********the line below where i am getting nullpointer exception
            con[count].concat(k+"\n");


    test--;count++;}

    for( i=0;i<con.length;i++)
        System.out.printf("%s\n",con[i]);
    }



    private static boolean prime(int k) {
        // TODO Auto-generated method stub
        if(k==2)
            return true;
        if(k%2==0)
            return false;
        for(int l=3;l<=Math.sqrt(k);l=l+2)
        if(k%l==0)
            return false;
        return true;
    }

}

please somebody help me that how to get rid from this exception.

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  1. Editorial Team
    Editorial Team
    2026-05-23T18:36:58+00:00Added an answer on May 23, 2026 at 6:36 pm

    String[] con=new String[test]; creates a new String array with test elements, and assigns it to con. However, this does not create any String objects at all – you have simply created an array where all elements are null. You must ensure that con[count] actually refers to a String before calling concat() on it; you can either do this by checking if it is null and assigning "" to it before calling concat(), or you can have a separate loop that puts an empty string into each element of con.

    By the way: concat() does not modify the String you call it on; it creates a new String and returns it, but you don’t do anything with the return value, so it gets thrown away. You should use += instead (which also creates a new String, but it will assign the new String to the array element).

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