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Home/ Questions/Q 7743563
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Editorial Team
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Editorial Team
Asked: June 1, 20262026-06-01T09:34:00+00:00 2026-06-01T09:34:00+00:00

import os import subprocess proc = subprocess.Popen([‘ls’,’*.bc’], stdout=subprocess.PIPE, stderr=subprocess.PIPE) out,err = proc.communicate() print out

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import os

import subprocess

proc = subprocess.Popen(['ls','*.bc'], stdout=subprocess.PIPE, stderr=subprocess.PIPE)

out,err = proc.communicate()

print out

This script should print all the files with .bc suffix however it returns an empty list. If I do ls *.bc manually in the command line it works. Doing [‘ls’,’test.bc’] inside the script works as well but for some reason the star symbol doesnt work.. Any ideas ?

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  1. Editorial Team
    Editorial Team
    2026-06-01T09:34:02+00:00Added an answer on June 1, 2026 at 9:34 am

    You need to supply shell=True to execute the command through a shell interpreter.
    If you do that however, you can no longer supply a list as the first argument, because the arguments will get quoted then. Instead, specify the raw commandline as you want it to be passed to the shell:

     proc = subprocess.Popen('ls *.bc', shell=True,
                                        stdout=subprocess.PIPE,
                                        stderr=subprocess.PIPE)
    
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