Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 6583131
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 25, 20262026-05-25T16:22:08+00:00 2026-05-25T16:22:08+00:00

In 32bit why is the address space limit 2^31? instead of 2^32?

  • 0

In 32bit why is the address space limit 2^31? instead of 2^32?

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-25T16:22:08+00:00Added an answer on May 25, 2026 at 4:22 pm

    The address space is not limited to 2^31. The address space is 2^32. What you are referring to is that the kernel reserves the upper 2GB leaving applications the lower 2GB.

    That’s simply an implementation detail of 32 bit Windows. In fact you can run Windows in /3GB mode in which case applications can access 3GB of memory.

    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

In 32bit mode application has access to 2GB of virtual address space. How would
when using the LARGEADDRESSAWARE flag, can my 32bit program access 4GB of address space,
I am confused over what is meant by virtual address space. In a 32
I saw that on a 64 bit windows OS the user virtual address space
What is the limitation on the virtual address space available to a process ?
Imagine this: a 32 bit application which has 2 GB address space and can
We are doing some 32bit * 32bit multiplication using the following algorithm Let us
OS: Windows 7 32bit So in like c++ one has a heap and a
What is the best 32bit hash function for relatively short strings? Strings are tag
Porting code from 32bit to 64bit. Lots of places with int len = strlen(pstr);

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.