Question

In a BlackBerry application, I am using this code in order to get a hash from a password:

        SHA256Digest sha256d = new SHA256Digest();
        byte[] passwordData = null;

        try {
            passwordData = password.getBytes("UTF-8");
        } catch (UnsupportedEncodingException e) {
            e.printStackTrace();
        }

        DigestOutputStream outputStream = new DigestOutputStream(sha256d, null);
        try {
            outputStream.write(passwordData);
        } catch (IOException e) {
            e.printStackTrace();
        }

        byte[] hashedValue = sha256d.getDigest();
        tempSHA256Password = new String(hashedValue);
        System.out.println(tempSHA256Password);

At the end of this code block, the tempSHA256Password is going to be something that looks like this: ëÇ#ÎiGê8óq =ßÝ÷<rê¨_FR»ã … so in no way what I am expecting. I am expecting a string that looks like this: ebc723ce6947ea38f371a03d0cdfddf73c840f7215eaa85f031446529bbb16e3

What am I doing wrong?

Answer 1

You can’t print directly a binary value:

tempSHA256Password = new String(hashedValue);
System.out.println(tempSHA256Password);

So if you want to convert it to hex you can use this method :

static final String HEXES = "0123456789ABCDEF";
public static String getHex( byte [] raw ) {
  if ( raw == null ) {
    return null;
  }
  final StringBuffer hex = new StringBuffer( 2 * raw.length );
  for ( final byte b : raw ) {
    hex.append(HEXES.charAt((b & 0xF0) >> 4))
     .append(HEXES.charAt((b & 0x0F)));
  }
  return hex.toString();
}

This method comme from here, you have also other example if interested.