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Home/ Questions/Q 778081
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Editorial Team
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Editorial Team
Asked: May 14, 20262026-05-14T19:42:32+00:00 2026-05-14T19:42:32+00:00

In a class, I have: private Foo bar; public Constructor(Foo bar) { this.bar =

  • 0

In a class, I have:

private Foo bar;
public Constructor(Foo bar)
{
    this.bar = bar;
}

Instead of creating a copy of bar from the object provided in the parameter, is it possible to include a pointer to bar in the constructor such that changing the original bar changes the field in this object?

Another way of putting it:

int x = 7;
int y = x;
x = 9;
System.out.print(y); //Prints 7.

It is possible to set it up so that printing y prints 9 instead of 7?

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  1. Editorial Team
    Editorial Team
    2026-05-14T19:42:32+00:00Added an answer on May 14, 2026 at 7:42 pm

    Your last example works that way because int is a primitive, it is copied by value. In the first example, “this.bar” would hold a copy of the reference (sort of pointer) to bar. So if you change the original bar (internally), the change will be reflected in your class. Try it.

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