Question

In a controller how can i validate a password so it contains at least 1 letter, 1 number, 1 special character and is at least 8 digits long. The code i am trying to use is as follows:

  boolean validatePassword(String password) {
    System.out.println("In validate")
   def pattern = /^.*(?=.{7,})(?=.*\d)(?=.*[a-zA-Z])(?=.*[!@#$%*&+()]).*$/
    def matcher = password =~ pattern
    System.out.println("HERERERE")
    return matcher.getCount() ? true : false
}

This does not work if says everything is invalid.
I have spring security ui plug in installed. Is there a way I can use its validation features?
I know i can use it to encode the password.

Answer 1

Rather than trying to do everything in one regex I’d split up the tests. Since in Groovy a Matcher coerces to boolean by calling find(), the following should work, and makes the intent clearer.

boolean validatePassword(String pass) {
  return (pass) && (pass.length() > 7) && (pass =~ /\p{Alpha}/) &&
         (pass =~ /\p{Digit}/) && (pass =~ /[!@#$%*&+()]/)
}