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Home/ Questions/Q 6662549
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T02:24:05+00:00 2026-05-26T02:24:05+00:00

In a data.frame (or data.table ), I would like to "fill forward" NAs with

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In a data.frame (or data.table), I would like to "fill forward" NAs with the closest previous non-NA value. A simple example, using vectors (instead of a data.frame) is the following:

> y <- c(NA, 2, 2, NA, NA, 3, NA, 4, NA, NA)

I would like a function fill.NAs() that allows me to construct yy such that:

> yy
[1] NA NA NA  2  2  2  2  3  3  3  4  4

I need to repeat this operation for many (total ~1 Tb) small sized data.frames (~30-50 Mb), where a row is NA is all its entries are. What is a good way to approach the problem?

The ugly solution I cooked up uses this function:

last <- function (x){
    x[length(x)]
}    

fill.NAs <- function(isNA){
if (isNA[1] == 1) {
    isNA[1:max({which(isNA==0)[1]-1},1)] <- 0 # first is NAs 
                                              # can't be forward filled
}
isNA.neg <- isNA.pos <- isNA.diff <- diff(isNA)
isNA.pos[isNA.diff < 0] <- 0
isNA.neg[isNA.diff > 0] <- 0
which.isNA.neg <- which(as.logical(isNA.neg))
if (length(which.isNA.neg)==0) return(NULL) # generates warnings later, but works
which.isNA.pos <- which(as.logical(isNA.pos))
which.isNA <- which(as.logical(isNA))
if (length(which.isNA.neg)==length(which.isNA.pos)){
    replacement <- rep(which.isNA.pos[2:length(which.isNA.neg)], 
                                which.isNA.neg[2:max(length(which.isNA.neg)-1,2)] - 
                                which.isNA.pos[1:max(length(which.isNA.neg)-1,1)])      
    replacement <- c(replacement, rep(last(which.isNA.pos), last(which.isNA) - last(which.isNA.pos)))
} else {
    replacement <- rep(which.isNA.pos[1:length(which.isNA.neg)], which.isNA.neg - which.isNA.pos[1:length(which.isNA.neg)])     
    replacement <- c(replacement, rep(last(which.isNA.pos), last(which.isNA) - last(which.isNA.pos)))
}
replacement
}

The function fill.NAs is used as follows:

y <- c(NA, 2, 2, NA, NA, 3, NA, 4, NA, NA)
isNA <- as.numeric(is.na(y))
replacement <- fill.NAs(isNA)
if (length(replacement)){
which.isNA <- which(as.logical(isNA))
to.replace <- which.isNA[which(isNA==0)[1]:length(which.isNA)]
y[to.replace] <- y[replacement]
} 

Output

> y
[1] NA  2  2  2  2  3  3  3  4  4  4

… which seems to work. But, man, is it ugly! Any suggestions?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-26T02:24:05+00:00Added an answer on May 26, 2026 at 2:24 am

    You probably want to use the na.locf() function from the zoo package to carry the last observation forward to replace your NA values.

    Here is the beginning of its usage example from the help page:

    library(zoo)
    
    az <- zoo(1:6)
    
    bz <- zoo(c(2,NA,1,4,5,2))
    
    na.locf(bz)
    1 2 3 4 5 6 
    2 2 1 4 5 2 
    
    na.locf(bz, fromLast = TRUE)
    1 2 3 4 5 6 
    2 1 1 4 5 2 
    
    cz <- zoo(c(NA,9,3,2,3,2))
    
    na.locf(cz)
    2 3 4 5 6 
    9 3 2 3 2 
    
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