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Home/ Questions/Q 3680456
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Editorial Team
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Editorial Team
Asked: May 19, 20262026-05-19T03:34:42+00:00 2026-05-19T03:34:42+00:00

In a django view I am filter out the content for each year to

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In a django view I am filter out the content for each year to display it in a chart via a template. Currently I am doing the calculation for each year manual, but there has to be a better way to right the code so that it just filters the content by year without having to hardcode the years. Also in the chart template I am also hardcoding the year and was wondering that could be written without hardcoding.

content_count_2006 = ContentItem.objects.filter(timestamp__year=2006).count()
content_count_2007 = ContentItem.objects.filter(timestamp__year=2007).count()
content_count_2008 = ContentItem.objects.filter(timestamp__year=2008).count()
content_count_2009 = ContentItem.objects.filter(timestamp__year=2009).count()
content_count_2010 = ContentItem.objects.filter(timestamp__year=2010).count()
content_count_2011 = ContentItem.objects.filter(timestamp__year=2011).count()

content_per_year = [content_count_2006, content_count_2007, content_count_2008, content_count_2009, content_count_2010, content_count_2011]


{% chart VerticalBarStack content_per_year %}
    {% axes type xy %}
    {% axes label "2006" "2007" "2008" "2009" "2010" "2011" %}
    {% color CCCCCC %}
{% endchart %}
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  1. Editorial Team
    Editorial Team
    2026-05-19T03:34:43+00:00Added an answer on May 19, 2026 at 3:34 am

    You could use a list comprehension:

    content_per_year = [ ContentItem.objects.filter(timestamp__year=y).count() \ 
        for y in range(2006, 2012) ]
    
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