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Home/ Questions/Q 971741
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Editorial Team
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Editorial Team
Asked: May 16, 20262026-05-16T03:00:42+00:00 2026-05-16T03:00:42+00:00

In a loop, I am trying to get a column vector of class factor

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In a loop, I am trying to get a column vector of class factor into numeric.

If there were not a loop, the code would look like

c1$values <- as.numeric(as.character(c1$values))

But how do I reference c1$values with a loop? I have tried two approaches:

get(paste('c',i,"$values", sep="")) 

just does not work even outside the loop, while

get(paste('c',"1", sep=""))[[1]]

works in itself (returns the column vector), but when trying to perform the operation:

assign(get(paste("c","1", sep=""))[[1]], as.numeric(as.character(get(paste("c","1", sep=""))[[1]])))

returns an error of “invalid first argument”.

Any ideas?

Thanks,

Roberto

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-16T03:00:43+00:00Added an answer on May 16, 2026 at 3:00 am

    Internally the $ operator is a function that can be explicitly called as "$" for getting and "$<-" for setting. assign is the opposite of get. So breaking things up into discrete steps we have:

    varname<-paste("c",1,sep="")
    obj<-get(varname)
    x<-"$"(obj,"values")
    x<-as.numeric(as.character(x))
    obj<-"$<-"(obj,"values",x)
    assign(varname,obj)
    

    But having data (such as an index) encoded into a variable name is not good practice. It might be a better idea to turn the c1,c2 etc. into a list or a data frame and then iterate over them. The conversion can be done by something like this:

    lapply(1:2,function(i) get(paste('c',i,sep='')))
    
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