Question

In a multidimensional array, is it possible to use the length variable to
measure different dimensions other than the first?

Answer 1

Yes. Length dimensions vary from row to row. You can do matrix[i].length to get the length of row i. If you know the matrix is square, all the row lengths will equals matrix[0].length anyways, so it doesn’t matter.

If you’re trying to iterate through all elements:

for(int i = 0; i < matrix.length; i++){
    for(int j < 0; j < matrix[i].length; j++){
        count += matrix[i][j];
    }
}

The same principle can be applied for any number of dimensions. For loops, you need 1 nested loop per dimension. For lengths, each bracketed part is actually a new element, so 3d array ar will yield a 2d array with ar[i], 1d with ar[i][j], and 0d (single element of the array type) with ar[i][j][k]