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Home/ Questions/Q 7862149
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Editorial Team
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Editorial Team
Asked: June 2, 20262026-06-02T23:00:59+00:00 2026-06-02T23:00:59+00:00

In a Rails view, one can use try to output only if there is

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In a Rails view, one can use try to output only if there is a value in the database, e.g

@model.try(:date)

And one can chain trys if, for example, the output is needed as a string

@model.try(:date).try(:to_s)

But what if I need to call a scoped format? I’ve tried

@model.try(:date).try(:to_s(:long))
@model.try(:date).try(:to_s).try(:long)

What is the correct syntax for this? And what is a good reference for more explanation?

Thanks

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  1. Editorial Team
    Editorial Team
    2026-06-02T23:01:03+00:00Added an answer on June 2, 2026 at 11:01 pm

    From the fine manual:

    try(*a, &b)
    […]
    try also accepts arguments and/or a block, for the method it is trying

    Person.try(:find, 1)
    

    So I think you want:

    @model.try(:date).try(:to_s, :long)
    

    This one won’t work:

    @model.try(:date).try(:to_s(:long))
    

    because you’re trying to access the :to_s symbol as a method (:to_s(:long)). This one won’t work:

    @model.try(:date).try(:to_s).try(:long)
    

    because you’re trying to call the long method on what to_s returns and you probably don’t have a String#long method defined.

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