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Home/ Questions/Q 760521
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Editorial Team
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Editorial Team
Asked: May 14, 20262026-05-14T15:43:40+00:00 2026-05-14T15:43:40+00:00

in a script i call another class with: Factory::folder(); but when i specify… dirname(__FILE__)

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in a script i call another class with:

Factory::folder();

but when i specify…

dirname(__FILE__)

…i get the library’s path, not the caller’s.

how can i have the caller’s path?

thanks

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  1. Editorial Team
    Editorial Team
    2026-05-14T15:43:41+00:00Added an answer on May 14, 2026 at 3:43 pm

    Use ReflectionClass. To be more specific, it’s method getFileName().

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