Question

In a web application using struts2 ejb hibernate, is it possible to tell the application to find or create an entity for a specific persistence-unit name, which is written in persistence.xml file, in the deployment time?

I have two persistence-unit in persistence.xml, and one datasource
(including two “local-tx-datasource”) xml file under the jboss node.

To clearify, I mean, I tried this;

@Entity  
@PersistenceContext(unitName="MY JNDI NAME specified in persistence.xml") 
public abstract class Vehicle {

and doesnt work.. Then tried this and etc..

@PersistenceContext(name="MY PERSISTENCE UNIT NAME specified in persistence.xml")

@PersistenceUnit(name="MY PERSISTENCE UNIT NAME specified in persistence.xml")

and also I tried these above with the “UnitName=..” instead of “name=..” but anything is worked for me…

[SOLVED]

<.exclude-unlisted-classes>true<./exclude-unlisted-classes>
has solved my problem

Answer 1

Update: Based on your comment (this is not what I understood from the original question), I don’t think you have any other option than disabling “discovery” and listing explicitly your entities in their respective persistence unit:

<?xml version="1.0" encoding="UTF-8"?>
<persistence
    xmlns="http://java.sun.com/xml/ns/persistence"
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xsi:schemaLocation="http://java.sun.com/xml/ns/persistence http://java.sun.com/xml/ns/persistence/persistence_2_0.xsd"
    version="2.0">

  <persistence-unit name="MyPu1" transaction-type="RESOURCE_LOCAL">
    <provider>org.hibernate.ejb.HibernatePersistence</provider>
    <class>com.mycompany.Foo</class>
    ...
    <exclude-unlisted-classes>true</exclude-unlisted-classes>
    <properties>
      <!-- H2 in memory -->
      <property name="javax.persistence.jdbc.driver" value="org.h2.Driver"/>
      <property name="javax.persistence.jdbc.url" value="jdbc:h2:mem:test"/>
      <property name="javax.persistence.jdbc.username" value="APP"/>
      <property name="javax.persistence.jdbc.password" value="APP"/>
      <property name="hibernate.hbm2ddl.auto" value="update"/>
    </properties>
  </persistence-unit>

  <persistence-unit name="MyPu2" transaction-type="RESOURCE_LOCAL">
    <provider>org.hibernate.ejb.HibernatePersistence</provider>
    <class>com.mycompany.Bar</class>
    ...
    <exclude-unlisted-classes>true</exclude-unlisted-classes>
    <properties>
      <!-- Derby server -->
      <property name="javax.persistence.jdbc.driver" value="org.apache.derby.jdbc.ClientDriver"/>
      <property name="javax.persistence.jdbc.user" value="APP"/>
      <property name="javax.persistence.jdbc.password" value="APP"/>
      <property name="javax.persistence.jdbc.url" value="jdbc:derby://localhost:1527/Pu2;create=true"/>
      <property name="hibernate.hbm2ddl.auto" value="update"/>
    </properties>
  </persistence-unit>
</persistence>

I’m not aware of any syntax at the entity level allowing to assign it to a persistence unit.

---

I’m not sure I understood what you’re trying to do but if you want to get an Entity Manager for a specific persistence unit injected, you should do:

@Stateless
public class FooBean implements Foo {
    @PersistenceContext(unitName="MyPu1")
    EntityManager em1;

    // ...
}

If this is not what you want, please clarify the question.