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Asked: May 11, 20262026-05-11T10:31:36+00:00 2026-05-11T10:31:36+00:00

In a WPF app that I’m writing using the MVVM pattern, I have a

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In a WPF app that I’m writing using the MVVM pattern, I have a background process that doing it’s thing, but need to get status updates from it out to the UI.

I’m using the MVVM pattern, so my ViewModel knows virtually nothing of the view (UI) that is presenting the model to the user.

Say I have the following method in my ViewModel:

public void backgroundWorker_ReportProgress(object sender, ReportProgressArgs e) {     this.Messages.Add(e.Message);     OnPropertyChanged('Messages'); } 

In my view, I have a ListBox bound to the Messages property (a List<string>) of the ViewModel. OnPropertyChanged fulfills the role of the INotifyPropertyChanged interface by calling a PropertyChangedEventHandler.

I need to ensure that OnPropertyChanged is called on the UI thread – how do I do this? I’ve tried the following:

public Dispatcher Dispatcher { get; set; } public MyViewModel() {      this.Dispatcher = Dispatcher.CurrentDispatcher; } 

Then adding the following to the OnPropertyChanged method:

if (this.Dispatcher != Dispatcher.CurrentDispatcher) {     this.Dispatcher.Invoke(DispatcherPriority.Normal, new ThreadStart(delegate     {         OnPropertyChanged(propertyName);     }));     return; } 

but this did not work. Any ideas?

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  1. 2026-05-11T10:31:37+00:00Added an answer on May 11, 2026 at 10:31 am

    WPF automatically marshals property changes to the UI thread. However, it does not marshal collection changes, so I suspect your adding a message is causing the failure.

    You can marshal the add manually yourself (see example below), or use something like this technique I blogged about a while back.

    Manually marshalling:

    public void backgroundWorker_ReportProgress(object sender, ReportProgressArgs e) {     Dispatcher.Invoke(new Action<string>(AddMessage), e.Message);     OnPropertyChanged('Messages'); }  private void AddMessage(string message) {     Dispatcher.VerifyAccess();     Messages.Add(message); } 
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