Question

In app I have:

LinearLayout linearLayout2 = (LinearLayout) findViewById(R.id.cvLinearLayout2);

and after:

linearLayout2.setVisibility(View.GONE);

I can’t find a way to bring linearLayout2 back.

Tried everything:

  linearLayout2.setVisibility(View.VISIBLE);
  linearLayout2.bringToFront();
  linearLayout2.getParent().requestLayout();
  linearLayout2.forceLayout();
  linearLayout2.requestLayout();
  linearLayout2.invalidate();

but with no results.
linearLayout2 have one parent linearLayout1, so I tried also:

  linearLayout1.requestLayout();
  linearLayout1.invalidate();

still with zero results. linearLayout2 stays GONE.
In my app I need to move linearLayout away, and then, after a while to redraw it again. Please help.

Answer 1

Setting a View’s visibility to GONE should not affect it’s ability to “come back” by using the method setVisibility(View.VISIBLE)

For example I have this code in one of my apps:

public void onCheckedChanged(CompoundButton checkBox, boolean isChecked{
    if(checkBox == usesLocationCheckBox)
    {
        View view = findViewById(R.id.eventLocationOptions);
        if(isChecked)
        {
            view.setVisibility(View.VISIBLE);
            usesTimeCheckBox.setEnabled(false);
        }
        if(!isChecked)
        {
            view.setVisibility(View.GONE);
            usesTimeCheckBox.setEnabled(true);
        }
    }}

And it works perfectly fine. Some other code your program is executing must be responsible. Edit your post with the relevant code, and we may be able to give you a better answer.