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Home/ Questions/Q 6074107
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Editorial Team
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Editorial Team
Asked: May 23, 20262026-05-23T10:20:43+00:00 2026-05-23T10:20:43+00:00

In bash this works: var1=abc But this gives an error: var*1=abc var*1=abc: command not

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In bash this works:

var1=abc

But this gives an error:

var*1=abc
var*1=abc: command not found

Why so? Why is the expression treated as a command?

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  1. Editorial Team
    Editorial Team
    2026-05-23T10:20:43+00:00Added an answer on May 23, 2026 at 10:20 am

    From http://www.gnu.org/software/bash/manual/bashref.html

    name

    A word consisting solely of letters, numbers, and underscores, and beginning with a letter or underscore. Names are used as shell variable and function names. Also referred to as an identifier.

    The value on the left hand side is not an identifier. It is an expression. Therefore that command (to evaluate the entire expression) is invalid.

    In other words, you can’t have asterisks in names, and you can’t generate a variable name by doing some math (multiplying).

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