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Editorial Team
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Editorial Team
Asked: June 18, 20262026-06-18T09:27:57+00:00 2026-06-18T09:27:57+00:00

In BST, if each node does not have a pointer to its parent, instead,

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In BST, if each node does not have a pointer to its parent, instead, have a pointer to its successor (also has left and right child pointer). How could we design an algorithm to get its parent based on the successor pointer?

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  1. Editorial Team
    Editorial Team
    2026-06-18T09:27:58+00:00Added an answer on June 18, 2026 at 9:27 am

    For a node n, we can repeatedly get the successor s until we get one that s.left == n. s is then the parent. If no such node is found, n is a right child and we repeatedly get the successor s, starting from the first element (easy to get by repeatedly calling e = e.left) until we get s.right == n, then s is the parent.

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