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Asked: May 10, 20262026-05-10T19:39:55+00:00 2026-05-10T19:39:55+00:00

In C++, a function’s signature depends partly on whether or not it’s const. This

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In C++, a function’s signature depends partly on whether or not it’s const. This means that a class can have two member functions with identical signatures except that one is const and the other is not. If you have a class like this, then the compiler will decide which function to call based on the object you call it on: if it’s a const instance of the class, the const version of the function will be called; if the object isn’t const, the other version will be called.

In what circumstances might you want to take advantage of this feature?

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  1. 2026-05-10T19:39:55+00:00Added an answer on May 10, 2026 at 7:39 pm

    This really only makes sense when the member function returns a pointer or a reference to a data member of your class (or a member of a member, or a member of a member of a member, … etc.). Generally returning non-const pointers or references to data members is frowned upon, but sometimes it is reasonable, or simply very convenient (e.g. [] operator). In such cases, you provide a const and a non-const versions of the getter. This way the decision on whether or not the object can be modified rests with the function using it, which has a choice of declaring it const or non-const.

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