Question

In C++, an object’s destructor is called at the closing “}” for the block it was created in, right? So this means that if I have:

while(some_condition)
{
    SomeClass some_object;
    some_object.someFunction();
    some_variable = some_object.some_member;
}

Then the destructor for the object created in one iteration of the loop will be called at the end of the loop before another object is created, correct?

Thanks.

Answer 1

Yes.

But you could have tested it yourself. This is a language feature that compilers are unlikely to get wrong.

#include <iostream>

struct S {
  S() { std::cout << "S::S()\n"; }
  ~S() { std::cout << "S::~S()\n"; }
};

int main () {
  int i = 10;
  while(i--) {
    S s;
  }
}