Question

In C#, how would I go about setting 2 bytes where the first 10 bits represent one decimal value and the next 6 represent a different decimal value?

So if the first value was ‘8’ (first 10 bits) and the second ‘2’ (remaining 6 bits), I need to end up with ‘0000001000 000010’ inside a byte array.

Thanks!
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Answer 1

UInt16 val1 = 8;
UInt16 val2 = 2;
UInt16 combined = (UInt16)((val1 << 6) | val2);

If you need it in a byte array, you can pass the result to the BitConverter.GetBytes method.

byte[] array = BitConverter.GetBytes(combined);