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Home/ Questions/Q 918179
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Editorial Team
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Editorial Team
Asked: May 15, 20262026-05-15T18:19:53+00:00 2026-05-15T18:19:53+00:00

In C# I can declare the following class A { int Field; } class

  • 0

In C# I can declare the following

class A {
    int Field;
}

class B : A {
    int Field2;
}

static int f(A a) { return a.Field; }
static int f(B b) { return a.Field + b.Field2; }

static void Main(string[] args) {
    A a = new A() { Field = 1 };
    A b = new B() { Field = 1, Field = 2};

    Console.WriteLine(f(a) + f(b));
}

In Haskell I would type out the above as

data A = A { field :: Int } | B { field :: Int, field2 :: Int }

f :: A -> Int
f (A a) = a
f (B a b) = a + b

main :: IO()
main = do putStrLn $ show (f(a) + f(b))
    where a = A 1
          b = B 1 2

What I don’t like about the Haskell counterpart is that I have to repeat field twice in the data definition of A (this becomes more tiresome as the number of fields increases that are present in A that need to be in B). Is there a more concise way in Haskell to write B as a subclass of A (that is somewhat similar to the C# way)?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-15T18:19:54+00:00Added an answer on May 15, 2026 at 6:19 pm

    If A has a lot of fields, one design that might make sense is to have two different datatypes for A and B, where a B contains an A, and then use a typeclass to define f. Like so:

    data A = A {field1 :: Int, field2 :: Int, ..., field9999 :: Int}
    data B = B {a :: A, field10000 :: Int}
    
    class ABC a where
        f :: a -> Int
    
    instance ABC A where
        f a = field1 a + field101 a
    
    instance ABC B where
        f b = f (a b) + field10000 b
    
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