Question

In C, I can put a log printf inside a function like this:

void xx_lock (int xx_flag)
{
  printf ("%s: START with %d\n", __FUNCTION__, xx_flag);
}

so I can copy the same line where I need in any function and it displays the function name in the log. I want something similar in Python. But if I use

__name__

the same way, it displays the module name, not the function name.

def xxx_lock(xx_flag=0)
    sys.stdout.write("%s: START with %d\n" % (__name__, xx_flag))

Is there some simple construct that I can use in that example to show the Python function name? To produce output like this:

xxx_lock: START with 1

Edited: added the parameter to the example.

Answer 1

katrielalex above is right that you should not attempt to do this the “C way”. Python has batteries included, so why not use them?

import logging, sys

logging.basicConfig(format="%(filename)s:%(funcName)s:%(message)s",level=logging.DEBUG,stream=sys.stderr)

def testFunc():
    logging.debug("entering")

testFunc()