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Editorial Team
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Editorial Team
Asked: May 30, 20262026-05-30T19:20:36+00:00 2026-05-30T19:20:36+00:00

In C++ if I do a logical OR (or AND) on two bitsets, for

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In C++ if I do a logical OR (or AND) on two bitsets, for example:

bitset<1000000> b1, b2;
//some stuff
b1 |= b2;

Does this happen in O(n) or O(1) time? Why?

Also, can this be accomplished using an array of bools in O(1) time?

Thanks.

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  1. Editorial Team
    Editorial Team
    2026-05-30T19:20:38+00:00Added an answer on May 30, 2026 at 7:20 pm

    It has to happen in O(N) time since there is a finite number of bits that can be processed in any given chunk of time by a given processor platform. In other words, the larger the bit-set, the longer the amount of time each operation will take, and the increase will be linear with respect to the number of bits in the bitset.

    You also end up with the same problem using the array of bool types. While each individual operation itself will take O(1) time, the total amount of time for N objects will be O(N).

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