Question

In C++:

If I want to add 0x01 to the string text I would do: text += (char)0x01;

If I want to add 0x02 to the string text I would do: text += (char)0x02;

If I want to add 0x0i (were i is an unsinged int between 0 and 9), what could I do?

EDIT: I probably wasn’t quite clear. So by 0x01, I mean the character given in Hex as 01. So in the above if i is the integer (in decimal) say 3, then I would want to add 0x03 (so this is not the character given in decimal as 48 + 3).

Answer 1

You can directly do

text += (char)i;

Because 0x0i == i if i is between 0 and 9.