In C++, if you have two variables a and b, you can do this to add b to a:
a += b;
How can you do the same thing in bash?
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In C++, if you have two variables a and b, you can do this to add b to a:
a += b;
How can you do the same thing in bash?
Surround the expression in double parenthesis, like so:
Alternatively, you could do something like:
or even: